服务器评测
方法一
1.使用cp命令
cp /home/usr/dir/{file1,file2,file3,file4} /home/usr/destination/
需要注意的是这几个文件之间不要有空格
1.具有共同前缀
cp /home/usr/dir/file{1..4} ./
复制的文件是file1, file2, file3, file4
方法二
1.使用Python脚本 shutil库
import os,sys,shutil
### copies a list of files from source. handles duplicates.
def rename(file_name, dst, num=1):
#splits file name to add number distinction
(file_prefix, exstension) = os.path.splitext(file_name)
renamed = “%s(%d)%s” % (file_prefix,num,exstension)
#checks if renamed file exists. Renames file if it does exist.
if os.path.exists(dst + renamed):
return rename(file_name, dst, num + 1)
else:
return renamed
def copy_files(src,dst,file_list):
for files in file_list:
src_file_path = src + files
dst_file_path = dst + files
if os.path.exists(dst_file_path):
new_file_name = rename(files, dst)
dst_file_path = dst + new_file_name
print “Copying: ” + dst_file_path
try:
# 复制操作主要就是这句
shutil.copyfile(src_file_path,dst_file_path)
except IOError:
print src_file_path + ” does not exist”
raw_input(“Please, press enter to continue.”)
def read_file(file_name):
f = open(file_name)
#reads each line of file (f), strips out extra whitespace and
#returns list with each line of the file being an element of the list
content = [x.strip() for x in f.readlines()]
f.close()
return content
src = sys.argv[1]
dst = sys.argv[2]
file_with_list = sys.argv[3]
copy_files(src,dst,read_file(file_with_list))
2. 将以上代码保存为move.py
3. 运行 $ python move.py /path/to/src/ /path/to/dst/ file.txt
4. file.txt 中定义要复制的文件名字，只要给出名字即可，不需要路径
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